问：
解方程x — 56 = 19 12 + x = 56 12x — 9x = 8.72x + 1 = 5 3x — x = 0.9 x — 34 = 112
答：
这是一组连续的方程式,我们需要逐一解开:
1. x - 56 = 19
x = 19 + 56 = 75
所以x = 75
2. 12 + x = 56
x = 56 - 12 = 44
所以x = 44
3. 12x - 9x = 8
12x - 9x = 3x = 8
x = 8/3 = 2
所以x = 2
4. 7x + 1 = 5
7x = 5 - 1 = 4
x = 4/7 = 0.57
所以x = 0.57
5. 3x - x = 0.9
3x - x = 2x = 0.9
x = 0.9/2 = 0.45
所以x = 0.45
6. x - 34 = 112
x = 112 + 34 = 146
所以x = 146
综上,依次解开每个方程,得出:
x1 = 75
x2 = 44
x3 = 2
x4 = 0.57
x5 = 0.45
x6 = 146
详细说明:
1. 方程x - 56 = 19:x代表未知数,56和19都是已知数。将19加到方程两边,得x = 19 + 56,所以x = 75
2. 同理,方程12 + x = 56:将12从方程右边减去,得x = 56 - 12,所以x = 44
3. 方程12x - 9x = 8:将9x从方程两边减去,得12x - 9x = 3x = 8,所以x = 8/3 = 2
4. 方程7x + 1 = 5,将1从方程两边减去,得7x = 5 - 1,所以x = 4/7 = 0.57
5. 方程3x - x = 0.9,将x从方程两边减去,得3x - x = 2x = 0.9,所以x = 0.9/2 = 0.45
6. 方程x - 34 = 112,将34加到方程两边,得x = 112 + 34,所以x = 146
希望上述详细的解释可以帮助您理解这个方程组的解答过程。如果您有任何其他疑问,欢迎提出。